(x-7)^2=2x^2-19x+35

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Solution for (x-7)^2=2x^2-19x+35 equation:



(x-7)^2=2x^2-19x+35
We move all terms to the left:
(x-7)^2-(2x^2-19x+35)=0
We get rid of parentheses
-2x^2+(x-7)^2+19x-35=0
We add all the numbers together, and all the variables
-2x^2+19x+(x-7)^2-35=0
We move all terms containing x to the left, all other terms to the right
-2x^2+19x+(x-7)^2=35

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